Question

a particle starts from rest accelerates at 2m/s2 for 10s and then goes for constant speed for 30s and then accelerates at 4m/s2 till it stops. what is the distance travelled by it??

Answer 1

For first 10 sec
distance s1 = 1/2 at^2
1/2×2×10×10 = 100m
And velocity reached=
v =u+at
v= 0+2×10 = 20m/s
For next 30s
s2= 20× 30 = 600m
Then under retardation of 4m/s^2
v^2 = 2as3
20× 20 = 2×4×s3
S3 = 50m
Total s1+ s2+ s3
100+600+50 = 750m

Answer 2

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