Question

A particle starts from rest and accelerates at constant rate of 5m/s2 fin the distance travelled in 4 seconds

Answer 1

According to the equations of motion
$s = ut + \frac{1}{2} a {t}^{2}$
$s = 0 \times 4 + \frac{1}{2} \times 5 \times {4}^{2}$
$s = 40$
So distance=40m

Answer 2

$a = 5ms {}^{ - 2} \\ t = 4sec \\ u = 0 \\ s = ut + \frac{1}{2} at {}^{2} \\ s = 0 + \frac{1}{2} \times 5 \times {4}^{2} \\ s = \frac{1}{2} \times 5 \times 16 \\ s = 5 \times 8 = 40m$
Hope its helps u

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