Question

A particle starts from rest and has an acceleration of 2m/s^2 for 10s.after that, it travels for 30 seconds with constant speed and then undergoes retardation of 4m/s^2 and comes back to rest. the total distance covered by the particle is ____

Answer 1



Here for the first part of journey u=0 , a=, t =10 sec

v=u + at  => v = 0 + 2 x 10= 20 m/sec

Distance = 0 + 1/2 x 2 x100= 100 m 

As per the question for the second part of journey as the speed is constant a=0 

thus distance s2= 20 x 30 = 600 m

for last part of journey.

u=20 m/sec , v =0 , a= 

 we have  

Answer 2

If we want to find the distance travelled than how to find it and no time is given.

Explanation: