Question

A particle starts from rest and has velocity kt after time
t. The distance travelled in time t is:
(A) kt square
(B) 2kt square
(C) k root t
(D) 1/2 kt square​

Answer 1

Answer:

+/- (1/2 K (t**2) ..(D).. 1/2 k.t^2

Explanation:

find out the value of acceleration and then equate by newton's 1 or 3 law of motion............. take img. as ref. for detailed sol.