A particle starts from rest and is accelerated uniformly. Find the ratio of distance travelled from in3rd and 5th second.
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Question:-
→ A particle starts from rest and is accelerated uniformly. Find the ratio of distance travelled from in3rd and 5th second.
Answer:-
»»» d3 : d5 = 5 : 9
Solution:-
Given:-
»»» The body starts from rest. u = 0
»»» The object is having a uniform acceleration throughout the journey.
To Find:-
★ The ratio of the distance travelled by the object in 3rd and 5th second.
Calculation:-
u = 0 ; a = ?
S 3 = u + a/2 [2(3) - 1]
= a/2 × 5
S5 = u + a/2 [2(5) - 1]
a/2 × 9
D3 : D5
a/2 × 5 : a/2 × 9
= 5 : 9
∴ Ratio of D3 : D5 = 5 : 9
Answered by
0
from Sn=u+a/2(2n-1)
then S3=0+a/2(5)=5a/2
S5=0+a/2(9)=9a/2
then ratio is equals to 5:9
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