Question

A particle starts from rest and its angular displacement (in rad) is given by theeta =t^2/20 +t/5 Calculate the angular velocity at the end of t=4 second

Answer 1

Answer:

Angular Velocity at t = 4 sec  = 0.6 rad/s rad/s

Explanation:

A particle starts from rest and its angular displacement (in rad) is given by theeta =t^2/20 +t/5 Calculate the angular velocity at the end of t=4 second

Angular displacement = t²/20 + t/5

Angular Displacement at t (0) = 0 rad

Angular diplacement in t (4) =  4²/20 + 4/5

= 16/20 + 4/5

= 4/5 + 4/5

= 8/5

= 1.6 Radians

θ = t²/20 + t/5

Angular velocity = d(θ)/dt = 2t/20 + 1/5

= t/10 + 1/5

at t = 4

Angular Velocity = 4/10 + 1/5  = 2/5 + 1/5 = 3/5

= 0.6 rad/s

Angular Velocity at t = 4 sec   = 0.6 rad/s

Answer 2

Answer:

Angular Velocity at t = 4 sec  = 0.6 rad/s rad/s

Explanation:

A particle starts from rest and its angular displacement (in rad) is given by theeta =t^2/20 +t/5 Calculate the angular velocity at the end of t=4 second

Angular displacement = t²/20 + t/5

Angular Displacement at t (0) = 0 rad

Angular diplacement in t (4) =  4²/20 + 4/5

= 16/20 + 4/5

= 4/5 + 4/5

= 8/5

= 1.6 Radians

θ = t²/20 + t/5

Angular velocity = d(θ)/dt = 2t/20 + 1/5

= t/10 + 1/5

at t = 4

Angular Velocity = 4/10 + 1/5  = 2/5 + 1/5 = 3/5

= 0.6 rad/s

Angular Velocity at t = 4 sec   = 0.6 rad/s