Question

a particle starts from rest and moves along a straight line with an accleration f varying as t^n if v be the velocity at a distance s from the starting point show that (n+1) v^2=(n+2) fs​

Answer 1

We use the relation:

v^2-u^2=2as

Body starts from rest and has constant acceleration. Hence

v^2=2as

v=√2as

hope it help