A particle starts from rest and
moves in a straight line whose
equation of motion is given by
s = 2t^2 - t - 1. The acceleration of
tins particle after 1 s will be
(a) 4 m/s2 (b) 6 m/s2
(c) 8 m/s2
d) 10 m/s2
Answers
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Answer:
S=2t²-t-1
V=ds/dt
V=d(2t²-t-1)/dr
V=4t-1
a=dv/dt
a=d(4t-1)/St
a=4.
So ACC.to this acceleration remains constant throughout the journey.
So correct answer is 4 m/s².
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