Question

a particle starts from rest and moves with a constant accleration of 6m/s².the displacement of the particle in 4th second is​

Answer 1

Answer:

u=0

a=6m/s^2

t=4 sec

displacement =final velocity - initial velocity

final velocity = v =u + at

v=0 + 6×4

v=24 m/s

displacement =24 m/s - 0m/s

24 m

Explanation:

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Answer 2

Answer:

24m

Explanation:

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