Question

A particle starts from rest and moves with a uniform acceleration of 5 m/s2 for 10 s and then it moves with a constant velocity for 4 s. Later it slows down and comes to rest in 5 s.
Draw the velocity graph for the motion of the body and calculate the total distance travelled?

Answer 1

Answer:

Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 s

Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at

Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2

Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2

Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5

Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2

Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2

Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 m

Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4

Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2

Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2

Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2 =40 m

Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2 =40 mDistance traveled in 5th s =(1/2)×5×5

Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2 =40 mDistance traveled in 5th s =(1/2)×5×5 2

Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2 =40 mDistance traveled in 5th s =(1/2)×5×5 2

Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2 =40 mDistance traveled in 5th s =(1/2)×5×5 2 =62.5 m=S

Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2 =40 mDistance traveled in 5th s =(1/2)×5×5 2 =62.5 m=S 2

Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2 =40 mDistance traveled in 5th s =(1/2)×5×5 2 =62.5 m=S 2

Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2 =40 mDistance traveled in 5th s =(1/2)×5×5 2 =62.5 m=S 2 −S

Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2 =40 mDistance traveled in 5th s =(1/2)×5×5 2 =62.5 m=S 2 −S 1

Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2 =40 mDistance traveled in 5th s =(1/2)×5×5 2 =62.5 m=S 2 −S 1

Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2 =40 mDistance traveled in 5th s =(1/2)×5×5 2 =62.5 m=S 2 −S 1 =(62.5−40)m=22.5m

Answer 2

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