Question

A particle starts from rest and moves with constant acceleration for 15 if the cover A certain distance first 5 second then and then covers S2 distance next 10 second find the relation between S1 and S2​

Answer 1

Answer:

s1=(1/2)a×5²=12.5a.The speed after 5s is 5a,As a is assumed the acceleration of the particle. Speed after 15s will be 15a.Where s2 can be calculated as s2={(5a+15a)×10}/2=100a

Now s2:s1=(100a)/(12.5a)=8.So s2=8s1.Ans

Explanation:

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