A particle starts from rest and moves with constant acceleration. It covers a distance x in two seconds and distance y in two seconds then, y=?
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Answered by
1
Answer: 3
Explanation:
Distance travelled in first two seconds, x,
x=u(2)+
2
1
a(2)
2
=
2
1
(4a) (As the u=0)
Now, distance travelled in next two seconds, y = distance travelled in four seconds − distance travelled in two seconds
y=s
u
−x=[u(4)+
2
1
a(4)
2
]−[u(2)+
2
1
a(2)
2
]
=
2
1
a[4
2
−2
2
]
=
2
a
×12
Finding ratio of y and x,
x
y
=
2
a
×4
2
a
×12
=3
⇒y=3x, hence n=3
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