Question

A particle starts from rest and moves with uniform acceleration. Then the ratio of distance
covered in nth sec, to that in n sec. is
n?
(2)
(4)
2n + 1
2n 1​

Answer 1

Answer:

(B)

Step-by-step explanation:

Distance travelled by a body in 'n'th second is

s

n

=u+

2

a

(2n−1)

Distance travelled in 'n' seconds is

s=un+

2

1

an

2

u is zero since the body starts from rest.

s

s

n

=

2

1

an

2

2

a

(2n−1)

Therefore, the ratio =

s

s

n

=

n

2

−

n

2

1