Question

A particle starts from rest and moving along a straight line travels 19m in the 10th second .The acceleration of the particle is given by-
(A) 1.9 m/sec^{2}
(B) 2 m/sec^{2}
(C) 3.8 m/sec^{2}
(D) 1 m/sec^{2}
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Answer 1

Answer:

B) 2 m/s^2

Explanation:

According to the given question,

n = nth second = 10

s = displacement = 19 m

u = initial velocity = 0 m/s

a = acceleration

And we are asked to find acceleration of the particle.

Here displacement is equal to distance as it's a linear motion without changing it's direction.

We know,

• s = u + 1/2 × a × (2n-1)

Putting the values we get,

• 19 = 0 + 1/2 × a ×(2×10-1)

• 19 = 19a/2

• 1 = a/2

• a = 2 m/s^2

Thus acceleration of the particle is 2 m/s^2 from the given conditions.