A particle starts from rest at the origin and moves along the positive X direction its acceleration a versus position x graph is shown in the figure.The velocity of the particle at x=6m is
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Answer:
Correct option is
C
(A), (B), (D)
Given initial velocity u=0 and acceleration is constant
At time t
v=0+at⇒v=at
also x=0(t)+
2
1
at
2
⇒x=
2
1
at
2
Graph (A) ; (B) and (D) are correct.
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here is ur answer hope you understand
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