A particle starts from rest at the point A(1, 2, -3) m and reaches at the point B(3, 4, 5) m. The magnitude of displacement of man is
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Answer :-
|AB| = 8.5 m
Explaination :-
Let i, j & k be unit vectors along X - axis, Y - axis & Z - axis.
A = i + 2j - 3k
B = 3i + 4j + 5k
Displacement of the man is calculated by -
AB = B - A
AB = (3i + 4j + 5k) - ( i + 2j - 3k)
AB = 2i + 2j + 8k
Magnitude of displacement is calculated by -
|AB| = √(2² + 2² + 8²)
|AB| = √(4 + 4 + 64)
|AB| = √(72)
|AB| = 2√18
|AB| = 8.48 m
From the options, 8.5 m is the most appropriate.
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