A particle starts from rest from origin and moves along a straight line with an acceleration given by a = 2(4-x) where x is distance from starting point. Find the displacement of the particle when it comes to rest again.
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Answer: 8 units.
Explanation:
In the attachment acceleration = dv/dt
where dv/dt is the differential coefficient of velocity w.r.t time at any instant of time. We know velocity = dx/dt where dx/dt is the differential coefficient of distance w.r.t time at any instant of time. C is the integration constant. As the particle started from rest therefore c =0. Refer to the attachment.
Attachments:

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