A particle starts from rest from the origin and moves along X-axis. Its position as a function of time is given x = 6t ^ 2 - t ^ 3 here is in meters and t is in seconds . The maximum displacement of the particle is
Answers
Answered by
2
Answer:
Acceleration of particle is given as a=12−2t
Velocity ∫
o
v
dv=∫
o
t
adt
Or ∫
o
v
dv=∫
o
t
(12−2t)dt
Or v−0=12t−t
2
We get v=12t−t
2
Position of particle ∫
o
x
dx=∫
o
t
vdt
Or ∫
o
x
dx=∫
o
t
(12t−t
2
)dt
Or x=6t
2
−
3
t
3
For particle to be at origin, x=0
Or 0=6t
2
−
3
t
3
⟹ t=18 s
Similar questions