Question

A particle starts from rest from x=2m at t= 0 along positive x-axis with acceleration of 2m/s^{2} the position of particles at t=2s is
a) x= 8m
b) x=4m
c) x=6m
d) x=2m

Answer 1

Answer:

Correct option D

Explanation:

Correct option is

D

30

v=x

2

+x

⇒

dx

dv

=2x+1

∴a=

dx

vdv

=(x

2

+x)(2x+1)

∴atr=2

a=(4+2)(4+1)

=30m/s

2