Question

A particle starts from rest has an acceleration of 1m/s2 for 5s. It then travels with constant speed for 15s. It then retards at 2m/s till it comes to rest. Its total distance travelled is​

Answer 1

Answer:

distance traveled in 5s=(1/2)×(1)×(5)^2=25/2

velocity at the end of 5s=2×(1)×(25/2)=25

distance traveled in 15s with this velocity=25×15=376

distance traveled after 15s to come to rest=s is given by (25)^2=2×(2)×s

s=625/4

Total distance traveled=(25/2)+376+(625/4)