Question

A particle starts from rest moves with constant acceleration for 15 second if it covers S1 distance in first 5 second then distance S2 in next 10 second then find the relation between S1 and S2

Answer 1

please mark brainliest

Answer 2

The relationship between the Distance $\bold{S_{1} \text { and } S_{2} \text { is } 8 S_{1}=S_{2}}$

SOLUTION:

The particle covers two distances $S_{1} \text { and } S_{2}$ in the time interval of t = 5sec and t = 10 sec respectively. Using Newton’s equation  

$s=u t+\frac{1}{2} a t^{2}$

u = 0 (particle starts from rest)  

For distance  $S_{1}$

$\begin{array}{l}{S_{1}=0 \times 5+\frac{1}{2} \times a \times 5^{2}} \\ {S_{1}=12.5 a \ldots \ldots \ldots \ldots \ldots \text { (i) }}\end{array}$

For the next distance $S_{2}$ the distance covered will be equal to the difference between the total distance and the distance travelled in another half.

$\begin{array}{l}{S_{2}=S_{15}-S_{5 s}} \\ {S_{2}=0 \times 15+\frac{1}{2} \times a \times 15^{2}-12.5 a} \\ {S_{2}=100 \mathrm{a} \ldots \ldots \ldots \ldots \ldots \ldots \text { (ii) }}\end{array}$

Dividing equation (i) and (ii)

$\begin{array}{l}{\frac{S_{1}}{S_{2}}=\frac{12.5 a}{100 a}}\\ \\ {8 S_{1}=S_{2}}\end{array}$