Physics, asked by SwarnagowriDns, 23 hours ago

A particle starts from rest moving along a straight line with a constant acceleration of 4 ms−2 . The ratio of the distances travelled in the 2nd and 2nd seconds is​

Answers

Answered by ITSSHUBHH
0

Answer:

s= 1/2at^2

S = 1/2*4*2*2

S = 8

S= a/2 (2n-1)

S= 4/2 (2*2-1)

S= 6

ratio= 8/6 = 4/3

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