Question

A particle starts from rest , moving with a=2t m/s² for initial 10 sec , after that it continue its motion with constant velocity for next 5 sec . Find total displacement in 15 sec

Answer 1

Answer:

Explanation:

a=2t

dv/dt= 2t

dv=2t dt

v=100 m/s

at t=10 sec v=100 m/s

v=100 m/s for next 5 sec

distance covered in this time = 500 m

a=2t

v=t^2+c

c=0 for t=10 and v=100

v=t^2

ds/dt = t^2

ds = t^2dt

s=1000/3 m

s=333.34 m

s1=333.34 m

total distance = 500+333.34

=833.34 m