A particle starts from rest under constant acceleration a its space average speed in between x=0 to x=x
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Answered by
2
We know that V^2 = U^2 + 2as
Since initially particle was at rest u=0
Hence equation becomes V^2 = 2 a s
Or V = √2 a s
It's a parabola symmetric about 's' axis
Answered by
0
Hey mate.....
here's your answer......
By using the third equation of motion...
v^2 + u^2 = 2as...
As the question describes very clearly that the particles starts from rest .. Hence initial velocity i.e
u = 0....
Thus v^2 = 2 as
v = √2as
Hope it helps ⭐
here's your answer......
By using the third equation of motion...
v^2 + u^2 = 2as...
As the question describes very clearly that the particles starts from rest .. Hence initial velocity i.e
u = 0....
Thus v^2 = 2 as
v = √2as
Hope it helps ⭐
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