Question

a particle starts from rest under uniform acceleration attains a velocity of 10m/s in 2s the distance travelled by the particle in 2s is​

Answer 1

Answer:

Hope it helps you.

Explanation:

a=v-u/t=10/2=5m/s

s=ut +1/2at^2

=0×2+1/2×5×4

=10m

Answer 2

Given,

Particle starts from rest.

Attains a velocity 10m/s in 2 seconds.

Undergone uniform acceleration.

To find,

The distance travelled by the particle in 2 seconds.

Solution,

We can simply solve this mathematical problem by using the following mathematical process.

Now,

Initial velocity (u) = 0 m/s (As, starts from rest.)

Final velocity (v) = 10 m/s

Time (t) = 2 seconds

Acceleration (a) = ?

Displacement (s) = ?

First of all, we have to calculate the acceleration. The value of acceleration is needed to calculate the displacement.

According, to the kinematics.

$a = \frac{(v - u)}{t}$

$a = \frac{(10 - 0)}{2}$

$a = \frac{10}{2}$

$a = 5 \: m/{s}^{2}$

Now, we have to calculate the value of displacement.

Again, according to the kinematics,

${v}^{2} = {u}^{2} + 2as$

${(10)}^{2} = {(0)}^{2} + (2 \times 5 \times s)$

$100 = 10s$

$10s = 100$

$s = 10 \: metres$

(This will be considered as the required value of displacement.)

Hence, displacement will be 10 metres.