Question

a particle starts from rest with a constant acceleration at a time t second, the speed is found to be 100m/s and one second later the speed become 150m/s . find the acceleration and distance traveled during the t+1th second​

Answer 1

Answer:

initial velocity =0

$initial \: velocity = 0 \\ accleration = \frac{150 - 100}{1} \\ a = 50m {s}^{ - 2} \\ in \: time \: (t + 1) \: seconds \\ u = 0 \\ v = 150m {s}^{ - 1} \\ a = 50m {s}^{ - 2} \\ t + 1 = ? \\ v = u + at \\ t + 1 = \frac{150}{50} \\ t + 1 = 3s \\ distance \: covered \: in \\ (t + 1)th \: second \\ s = u + \frac{a}{2} (2n - 1) \\ s = 25(5) \\ s = 125m$