Question

A particle starts from rest with constant
acceleration and its velocity after t second is v.
The displacement of the particle in last two second
of its motion is equal to​

Answer 1

3rd eqn of motion ;-

s = ut + 0.5 a t^2

s = 0 + 0.5 × 4 × a

s = 2a , where a is acceleration and s is displacement.