Question

A particle starts from rest with constant
acceleration and its velocity after t second is v.
The displacement of the particle in last two second
of its motion is equal to​

Answer 1

Answer:

here is the ans

Explanation:

nce particle starts from rest

Initial velocity (u)=0m/s

The distance in n sec

S (n) = un + 0.5 an^2

s(n) = (an^2) / (2)

The distance in( n-2) sec

S (n-2) = { a (n-2)^2 } / {2}

S(n) - S (n-2) = 2a (n-1)…………..(I)

Equation (i) is the displacement of body in last 2 second

From question

Velocity (V) = u + an

V = an

a= V/n…….(ii)

From equations (I) and (ii)

{ 2 V (n-1) } / n