A particle starts from rest with constant acceleration what is the ratio of the distance covered by the partical in 1st 2nd 3rd 4th and 5th seconds of its motion ?
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Explanation:
if thr is constant acceleration u=o
then s=1/2at^2
at 1st sec s=a/2
2nd =2a
3rd. =9a/2
4th. =8a
5th. =25a/2
1:2:3:4:5:=1:4:9:16:25
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