Question

A particle starts from rest with uniform acceleration. Its displacement after t seconds is given by

x = 3t2 + 6t + 9 (in metres)

Calculate the magnitude of its (a) initial velocity, (b) velocity when t =2s, (c) initial acceleration and (d) displacement

when t = 4s.​

Answer 1

Explanation:

Given equation of path of particle is x=7t

2

+5t+2

Now,

v=

dt

dx

=14t+5.

And initial velocity is the velocity of particle at time t=0. Hence ;

v

i

=14(0)+5=5ms

−1

So the magnitude of Initial velocity is 5ms

−1