A particle starts from the origin, goes along the X-axis to the point (30m, 0) and then returns along the same line to the point (-30 m, 0) .
Find the distance and displacement of the particle during the trip.
Answers
Answered by
47
distance travelled = 30+30-(-30) = 90m ( negative sign because object travels in negative direction)
displacement = -30m
as, the particle travels 30m more but in negative direction
hope this helps
displacement = -30m
as, the particle travels 30m more but in negative direction
hope this helps
Anonymous:
displacement = -30 m as the particle moves along the same line in negative direction
Them what about displacement
distance = 90 m as the object travels positive 30m then returns to its origin (travelling 30m) and then again cover 30m in negative direction ....... that gives us 90m
Thanks! @kandarp1 for explaining !
Ok thanks a lot
as we know that displacement can be in negative but distance can't so , we get the answer distance = 90m and displacement = -30m
ur welcome
Ok
and thanks to u for not reporting my answer........
It's ok
Answered by
32
Hi ,
distance from origin to ( 30, 0 ) = 30 m---( 1 )
again
it returns from ( 30 , 0 ) to
( -30 , 0 )
distance travelled=30 + 30 = 60m---( 2 )
displacement of the particle = ( 1 ) + ( 2 )
= 30 + ( -60 )
( since 60 m is opposite
direction )
= 30 - 60
= - 30 m
I hope this helps you.
:)
distance from origin to ( 30, 0 ) = 30 m---( 1 )
again
it returns from ( 30 , 0 ) to
( -30 , 0 )
distance travelled=30 + 30 = 60m---( 2 )
displacement of the particle = ( 1 ) + ( 2 )
= 30 + ( -60 )
( since 60 m is opposite
direction )
= 30 - 60
= - 30 m
I hope this helps you.
:)
Sir , distance = 90 m
Ok
Similar questions