Question

A particle starts from the origin with velocity
44 ms on a straight horizontal road. Its
acceleration varies with displacement as shown.
The velocity of the particle as it passes through the
position x = 0.2 km is

(1) 16 ms
(3) 20 ms -1
(2) 18 ms
(4) 22 ms​

Answer 1

Answer:

Explanation:

Since,the relation between acceleration and velocity in the terms of x is , integration of adx = integration of vdv, so through this we will find the area of a-x curve, the total area from origin to x=200m is,. 140=(v^2 -44)/2 so through this we get velocity at x=0.2km i.e 18m/s