Question

a particle starts from the point (0m,3m) and moves with uniform velocity of ms after 4sec the angular velocity of particle about the origin would be​

Answer 1

Answer:

Step-by-step explanation:

Initial posion vector 0i + 8j

Velocity acts only along the x axis i.e

V=3i

Hence the angular momentum remains constant and

L=R(perpendicular)*(cross) mv

= 8j * 3i

= -24k. (i*j=k , j*i= -k )

Hope it helps