Question

A particle starts from the point zero meet me and moves with uniform velocity of 3 icap metre per second after 5 second the angular velocity of the particle about the origin will be

Answer 1

Particle starts from (0m , 8m) from rest with uniform velocity 3 m/s in the x-direction so after 5 sec the particle will traverse a distance along x-axis is 3*5=15 m so new position of the particle is ​(15m , 8m). So the distance of this new position to the origin is

√(15−0)^2+(8−0)^2 =√225+64=√289=17 m.

Thus the angular velocity about origin is given by 

ω=v/r

ω=3/17rad /s