a particle starts its motion along positive x axis at t=0 it has x=0 v=10m/s and a=5m/s2.what is the distance travelled by the particle in first three seconds
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Answered by
0
u = 10m/s
a = 5m/s^2
S = ut + 0.5at^2
S = 10*3 + 0.5*5*3^2
S = 30 + 22.5
S = 52.5 m
Distance travelled in first three seconds is 52.5 m
a = 5m/s^2
S = ut + 0.5at^2
S = 10*3 + 0.5*5*3^2
S = 30 + 22.5
S = 52.5 m
Distance travelled in first three seconds is 52.5 m
Answered by
3
H e y a ! ! !
YOUR ANSWER - 52 . 5 m
SOLUTION -:
u = 10m/s
a = 5m/s^2
S = ut + 0.5at^2
S = 10*3 + 0.5*5*3^2
S = 30 + 22.5
S = 52.5 m
Hence , Distance travelled in first three seconds is 52.5 m
#hope it helps !
YOUR ANSWER - 52 . 5 m
SOLUTION -:
u = 10m/s
a = 5m/s^2
S = ut + 0.5at^2
S = 10*3 + 0.5*5*3^2
S = 30 + 22.5
S = 52.5 m
Hence , Distance travelled in first three seconds is 52.5 m
#hope it helps !
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