Question

A particle starts its motion from rest under the action of a constant force if the distance covered in first 10 seconds is S1 and that covered in the first 20 second is S2 then.
​

Answer 1

$\huge {\bold {\red {ASSALAMUALAIKUM}}}$

☺❤☺

___________________________________________

$\huge {\bold {\red {s0IUtion...}}}$

___________________________________________

Given u = 0

✒Distance travelled in 10 s,

S1 = $\frac{1}{2a}$ x 10²

= 50a

✒Distance travelled in 20 s,

S2 = $\frac{1}{2a}$ x 20²

= 200a

then S2 = 4S1✓

___________________________________________

$INSHAALLAH it will help you!$

$\huge {\bold {\red {A.K.}}}$

Answer 2

Explanation:

Body starts from the rest

so initial velocity U = 0 m/sec

Particle is moving in a straight line with constant force

Distance covered

S = ut + 1/2 at²

S = 0×t + 1/2 at²

S = 1/2 at²

S1 in first 10 seconds = t

S1 = 1/2 × a ×10²

S1 = 50a

S2 = 1/2 × a × 20²

S2 = 200a

So now S1/S2

S1/S2 = 50a/200a

S1/S2 = 1/4

S2 = 4S1