A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 sec is s1
and that covered in the first 20 sec is s2, then
(a) s2 = 2s1
(b) s2 = 3s1
(C) s2 = 4s1
(d) s2 =s1
Answers
Answered by
1
Explanation:
A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is S1 and that covered in the first 20 seconds is S2 then:
Answered by
3
Answer:
s1 = 1/2 a ( 10) ^ 2
s1 = 50 a
s2 = 1/2 a (20 ) ^2
s2 = 200 a
Therefore ,
s2 = 4 s1
Hence , option 'c' is correct .
I hope it helps .
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