Question

A particle starts moving along a circle of radius (20/π)m with constant tangential acceleration.if velocity of the particle is 50 m/s at the end of the second revolution after motion has began,the tangential acceleration in m/s^2 is​

Answer 1

Answer:

A particle starts moving along a circle of radius (20/π)m with constant tangential acceleration. If speed of the particle is 50m/s at the end of the second revolution after motion has began, the tangential acceleration in m/s

2

is:

Answer 2

Answer:

a = 15.625 m/s²

Explanation:

r = $\frac{20}{\pi }$ m

v = 50 m/s

θ = 2 revolutions = 4π rad.

Using Equation :

ω² = ω₀² + 2αθ     ..(ω₀=0)

ω² = 2αθ     ..(ω=v/r  &  a=rα)

a = v²/2rθ

a = 2500π/160π

a = 15.625 m/s²