Question

A particle starts moving along a circle of radius (20 / )

 m with constant tangential accleration. If speed

of the particle is 50 m/s at the end of the second revolution after motion has began, the tangential acceleration
​

Answer 1

Answer:

a = 15.625 m/s²

Explanation:

r = $\frac{20}{\pi }$ m

v = 50 m/s

θ = 2 revolutions = 4π rad.

Using Equation :

ω² = ω₀² + 2αθ     ..(ω₀=0)

ω² = 2αθ     ..(ω=v/r  &  a=rα)

a = v²/2rθ

a = 2500π/160π

a = 15.625 m/s²