A particle starts moving from a position of rest under constant acceleration. If it travels a distance 'x' in 't' sec, what distance will it travel in next t sec ?
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Answered by
73
s=ut+1/2at^2
so intially u=0
so s=1/2at^2. (let this be x)
now s'=1/2a(2t)^2= 4/2at^2. (so accordingly this would be 4x)
so s'-s=3x
so intially u=0
so s=1/2at^2. (let this be x)
now s'=1/2a(2t)^2= 4/2at^2. (so accordingly this would be 4x)
so s'-s=3x
Answered by
17
Answer:3x
Explanation:
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