Question

A particle starts moving rectilinearly at a time t=0 such that its velocity V changes with the time t according to the equation V =t^2-t where t is in the second and V is in the metre per second. the time interval for which the particle retards is?
answer of this question is 1 /2 greater than t greater than 1.


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Answer 1

Hey mate here is your answer

v=t^2-t

a=dV/dt=2t-1

a<0

2t-1<0

t<1/2

Therefore time interval

0<t<1/2

Answer 2

Answer:

Explanation:

this may help