Question

A particle starts moving with a constant angular acceleration in a circular path. The time at which the magnitudes of tangential and radial acceleration are equal is:

Answer 1

Answer:

1/√(angular acceleration) the solution is in the image

Answer 2

Given that Constant angular acceleration =α

We know that

$ω=ω_o+αt  \\ \sf Here ω0=0 \\ω=αt \\ rv=αt \\ v=αtr$

Now tangential acceleration = centripetal acceleration

$αr= \frac{r}{ {v}^{2} } \\ αr = \frac{ { \alpha }^{2} t {}^{2} {r}^{2} }{r} \\ t= \frac{1}{ \sqrt{a} }$