Question

a particle starts moving with acce. 2m/s^2.distance travelled by it in 5th half second is - .a.1.25 m .b. 2.25 m .c.6.25 m .d. 30.25 m

Answer 1

Given, 

Acceleration = 2m/s²

Intial velocity u = 0 m/s

Given time = 5th half second ⇒ 5x1/2 = 2.5s

By using, Sₓ = ut + (1/2)at²

                S₅ = (0)5 + (2)(2.5)²/2

                S₅ = 0+(2)(6.25)/2

                S₅ = 6.25m

So option c (6.25m) is correct.

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