Question

a particle starts moving with accelaration 2m per second distance travelled by it in 5th half second is solve using Sn=u+a/2(2n-1)​

Answer 1

Answer:

Distance travelled in 5th half second = Distance travelled in 2.5 seconds - Distance travelled in 2 seconds

= 0.5a (t₁² - t₂²)

= 0.5 * 2 * (2.5² - 2²)

= 2.25m