A particle starts moving with acceleration 2 metre per second square what is the distance travelled by it in 5th half second
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Given,
Acceleration = 2m/s²
Intial velocity u = 0 m/s
Given time = 5th half second ⇒ 5x1/2 = 2.5s
By using, Sₓ = ut + (1/2)at²
S₅ = (0)5 + (2)(2.5)²/2
S₅ = 0+(2)(6.25)/2
S₅ = 6.25m
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sid949:
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