A particle starts moving with acceleration 2m/s^2. Distance travelled by it in 5th half second is
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Distance travelled in 5th half second = Distance travelled in 2.5 seconds - Distance travelled in 2 seconds
= 0.5a (t₁² - t₂²)
= 0.5 * 2 * (2.5² - 2²)
= 2.25m
= 0.5a (t₁² - t₂²)
= 0.5 * 2 * (2.5² - 2²)
= 2.25m
n2n:
why we subtract plzzzzzzzzzzz tell
tell why we subtract
see me question
its fourmula
kis ka formula h
I m asking _ distance travelled in 2.5-2
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Answer:
Explanation:
Distance travelled in 5th half second = Distance travelled in 2.5 seconds - Distance travelled in 2 seconds
= 0.5a (t₁² - t₂²)
= 0.5 * 2 * (2.5² - 2²)
= 2.25m
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