Question

A particle starts moving with acceleration 2m/s distance travelled by it in 5th half second is: A1.25 m b 2.25 m c 6.25 m d 30.25 mAnswer is b.but how?

Answer 1

given
a=2m/S
U=0
t=5th half second
$\frac{1}{2} \times 5 = 2.5sec$
hence using second equation of motion
$s = ut + \frac{1}{2} a {t}^{2} \\ = s = \frac{1}{2} \times a \times {t}^{2} \\ = \frac{1}{2} \times 2 \times {(2.5)}^{2} \\ = 6.25m$