Question

A particle starts rotating from rest and its angular displacement is given by theta =t²/40+t/5. Then the angular velocity (w =d theta/dt ) at the end of 10 s is :​

Answer 1

Answer:

$\frac{dtheta}{dt} = \frac{d}{dt} ( \frac{ {t}^{2} }{40} + \frac{t}{5} ) \\ \\ = \frac{2t}{40} + \frac{1}{5} \\ \\ = \frac{1}{2} + \frac{1}{5} \: \: (t = 10)$

= 7/10= 0.7

Answer 2

Answer:

∅= t²/40+t/5

v= d∅/dt= d/dt(t²/40+t/5)

v=2t/40+1/5

t=10sec

v=2(10)/40+1/5

v=20/40+1/5

v=1/2+1/5

v=5+2/10

v=7/10

v=0.7