Question

A particle starts to move in a straight line from a point with velocity 10 metre per second and acceleration - 2 metre per second square find the position and velocity of particles at
time =5sec,time,10sec​

Answer 1

Answer:

v=dx/dt=3t² + 2t + 10 ...........(1)

if we integers eng.(1) . we get ,x =t³ +t² +10t + c......(2)

where c is constant of integration, which is do be evalvated using the given condition, at t =0 ,x = 20.

we get c= 20 hence , x =t³ +t² +10t +20 .........(3) displacement at t = 1, x =1 +1 +10 +20= 32 acceleration is obtained by different eng. (1) dv/dt =6t +2.