Question

A particle starts to move in a straight line from a point with velocity 10 M per second and acceleration - 2 metre per second square find the position and velocity of the particle at.....t=5sec...t=70sec

Answer 1

Answer:

when t=5

x=35m

when t=70

x=5600m

Explanation:

x=v1*t+1/2at^2

v1=10m/s

a=2m/s^2

when t=5

x=10*5+1/2*2*25

x=35m

when t=70

x=10*70+1/2*2*4900

x=5600m